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Question

If y=|cosx|+|sinx| , then dydx at x=2π3 is

A
12(3+1)
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B
2(31)
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C
12(31)
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D
none of these
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Solution

The correct option is A 12(3+1)
y=|cosx|+|sinx|

at x=2π3,

y=cosx+sinx

now,dydx=sinx+cosx

dydx=sin2π3+cos2π3

dydx=32+12

dydx=12(3+1)

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