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Question

If y=sin1(2x1+x2) then find dydx

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Solution

y=sin1(2x1+x2)
Differentiating above equation w.r.t. x, we have
dydx=11(2x1+x2)2(2(1+x2)2x(2x)(1+x2)2)
dydx=1+x2(1+x2)24x2(2+2x24x2(1+x2)2)
dydx=1(x21)2(2(1x2)1+x2)
dydx=1(x21)(2(1x2)1+x2)
dydx=21+x2

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