If y=sin^3t then find dy/dz

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\frac{d y}{d x}

x = {sin}^{3} t, y = {cos}^{3} t

x = \frac{{sin}^{3} t}{\sqrt{cos 2 t}}, y = \frac{{cos}^{3} t}{\sqrt{cos 2 t}}

\frac{d y}{d x}

x = \frac{{sin}^{3} t}{\sqrt{cos 2 t}}, y = \frac{{cos}^{3} t}{\sqrt{cos 2 t}}

\frac{d y}{d x}

d = \frac{d y}{d x}

x = \frac{{sin}^{3} t}{\sqrt{cos 2 t}}

y = \frac{{cos}^{3} t}{\sqrt{cos 2 t}}

y = \frac{1}{a - z}

\frac{d z}{d y}

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