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Question

If y=tan1(2x+11+22x) then dydx at x=0 is

A
110log2
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B
15log2
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C
110log2
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D
log2
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Solution

The correct option is D log2
Given,
y=tan1(2x+11+22x)

or, y=tan1(2.2x1+(2x)2)

or, y=2tan1(2x)

Now, dydx=21+(2x)2×2x×log2.

And dydxx=0=21+1×log2=log2.

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