CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If y=x-1 log x-1-x+1 log x+1, prove that dydc=log x-11+x

Open in App
Solution

We have, y=x-1 logx-1-x+1 logx+1
Differentiating with respect to x,
dydx=ddxx-1 logx-1-x+1 logx+1 =x-1ddxlogx-1+logx-1ddxx-1-x+1ddxlogx+1+logx+1ddxx+1 =x-1×1x-1ddxx-1+logx-1×1-x+1×1x+1×ddxx+1+logx+11 =1+logx-1-1+logx+1 =logx-1-logx+1 =logx-1x+1 So, dydx=logx-1x+1

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
States of Matter
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon