If z1 - 2 - i- z2 - 1 - i- find -z1 - z2 - 1z1 - z2 - i-

Given, z_1=2 i,z_2=1+i .Now, |z_1 + z_2 + 1z_1 + z_2 + i| =|z_1 + z_2 + 1||z_1 + z_2 + i| [ Using property of complex number] =|4||3+i| [ Sin ...

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Modulus of a Complex Number

If z1 = 2 -...

Question

If $z_{1} = 2 - i, z_{2} = 1 + i$ , find $∣ ∣ ∣ \frac{z_{1} + z_{2} + 1}{z_{1} + z_{2} + i} ∣ ∣ ∣$ .

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z_{1} = (2 - i)

z_{2} = (1 + i),

∣ ∣ ∣ \frac{z_{1} + z_{2} + 1}{z_{1} - z_{2} + i} ∣ ∣ ∣

z_{1} = (2 - i)

z_{2} = (1 + i),

∣ ∣ ∣ \frac{z_{1} + z_{2} + 1}{z_{1} - z_{2} + i} ∣ ∣ ∣

If $z_{1} = 2 - i$ and $z_{2} = 1 + i$ , find $∣ ∣ \frac{z_{1} + z_{2} + 1}{z_{1} - z_{2} + 1} ∣ ∣$

$If z + x + i y then (z) = \sqrt{x^{2} + y^{2}} z_{1} = 2 - i, z_{2} = 1 + i, find ∣ ∣ \frac{z_{1} + z_{2} + 1}{z_{1} - z_{2} + i} ∣ ∣ .$

z_{1} = (1 + i)

z_{2} = (1 - i)

\frac{z_{1}}{z_{2}}

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