If $z_{1}, z_{2}, z_{3}, z_{4}$ are vertices of a parallelogram respectively, then

z_{1} + z_{4} = z_{2} + z_{3}

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z_{1} + z_{3} = z_{2} + z_{4}

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z_{1} + z_{2} = z_{2} + z_{4}

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z_{1} + z_{3} = z_{3} + z_{4}

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Solution

The correct option is B $z_{1} + z_{3} = z_{2} + z_{4}$
We know that for the parallelogram diagonals are bisector of each other
$∴ \frac{z_{3} + z_{1}}{2} = \frac{z_{2} + z_{4}}{2}$
$z_{3} + z_{1} = z_{2} + z_{4}$

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If z1,z2,z3,z4 are vertices of a parallelogram respectively, then

The correct option is B z1+z3=z2+z4We know that for the parallelogram diagonals are bisector of each other∴z3+z12=z2+z42z3+z1=z2+z4

If $z_{1}, z_{2}, z_{3}, z_{4}$ are vertices of a parallelogram respectively, then

The correct option is B $z_{1} + z_{3} = z_{2} + z_{4}$
We know that for the parallelogram diagonals are bisector of each other
$∴ \frac{z_{3} + z_{1}}{2} = \frac{z_{2} + z_{4}}{2}$
$z_{3} + z_{1} = z_{2} + z_{4}$