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Question

If z=3+2i, then value of 3z313z2+9z+65 is 


A
0
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B
1
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C
2
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D
3
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Solution

The correct option is A 0
Given : 3z313z2+9z+65
Now, 
z=3+2i(z3)2=4i2z26z+13=0(1)

Using equation (1), we get
3z313z2+9z+65=3z(z26z+13)+5z230z+65=0+5(z26z+13)=0

Mathematics

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