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(II) $$CH_3CH_2CH_2CH_2Br$$

Arrange the following compounds in increasing order of their boiling points:

939462_658ee81239824a95b683495b7c377f5b.png


A
(II) < (I) < (III)
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B
(I) < (II) < (III)
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C
(III) < (I) < (II)
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D
(III) < (II) < (I)
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Solution

The correct option is B (III) < (I) < (II)
More the surface area more will be boiling point i.e. branching decreases boiling point because surface area decreases due to branching which result in decreases in attraction.
1032483_939462_ans_8bd8b72fc997485d8c38a7b15d9dcd25.png

Chemistry

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