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Question 3 (iii)
Form the pair of linear equations for the following problems and find their solution by substitution method:
The coach of a cricket team buys 7 bats and 6 balls for Rs 3800. Later, she buys 3 bats and 5 balls for Rs 1750. Find the cost of each bat and each ball.


Solution

Let cost of each bat = Rs x
Cost of each ball = Rs y
Given that coach of a cricket team buys 7 bats and 6 balls for Rs 3800.
7x + 6y = 3800
 6y = 3800 - 7x
Dividing by 6, we get
y=38007x6 … (i)
Given that she buys 3 bats and 5 balls for Rs 1750 later.
3x + 5y = 1750 ----(ii)
Substituting  the value of y in equation (ii), we get 
3x+5(38007x)6=1750
Multiplying by 6, we get
 18x + 19000 - 35x = 10500
 -17x =10500 - 19000
 -17x = -8500
 x=850017
 x = 500
Putting this value in equation (i), we get
y=(38007×500)6
 y=3006
 y = 50
Hence, cost of each bat = Rs 500 and cost of each balls = Rs 50.
 

Mathematics

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