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Question 9 (iii)
In parallelogram ABCD, two points P and Q are taken on diagonal BD such that DP=BQ (see the given figure) Show that:

ΔAQBΔCPD


Solution

In ΔAQBΔCPD,
ABQ=CDP (Alternate interior angles for AB||CD)
AB=CD (Opposite sides of parallelogram ABCD)
BQ=DP( Given)
ΔAQBΔCPD (Using SAS congruence rule)

 

Mathematics

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