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Question

Question 82 (iii)

Subtract

2ab2c2+4a2b2c5a2bc2 from10a2b2c+4ab2c2+2a2bc2


Solution

We have, 
2ab2c2+4a2b2c5a2bc2 and10a2b2c+4ab2c2+2a2bc2
The required difference is given by
(10a2b2c+4ab2c2+2a2bc2)(2ab2c2+4a2b2c5a2bc2)
=10a2b2c+4ab2c2+2a2bc22ab2c24a2b2c+5a2bc2
=(10a2b2c4a2b2c)+(4ab2c22ab2c2)+(2a2bc2+5a2bc2)
                                                                                     [grouping like terms]
=14a2b2c+2ab2c2+7a2bc2


Mathematics
NCERT Exemplar
Standard VIII

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