Question

In a $3$-digit number, the ten's digit is thrice the unit's digit and hundred's digit is equal to the unit's digit. If the sum of its all three digits is $10$, then find the reversed number.

• A. $262$
• B. $219$
• C. $393$
• D. $290$

Answer 1

The correct option is A $262$

Let the number be $abc$ i.e., $100a+10b+c$
Where unit digit $=c$, ten's digit $=b$ and hundred's digit $=a$.
Given $b=3c$ and $a=c$
$a+b+c=10$---(1)
Substitute the values of $b$ and a in equation (1), we get
$c+3c+c=10$
$5c=10$ (Divide both the sides by $10$)
$c=2$
Therefore, $b=3c=3\times 2=6$
$a=c=2$
Hence, the required $3$-digit number is $262$.
So, the reversed number is $262$.