In a AC circuit the current is given by i-5sin100t-2 and V-200sin 100t V then power consumption is

The correct option is D 0 W V=200sin (100 t) I=5sin(100t π2) θ=0 ( π2) θ=π2 P=V_rmsI_rmscosϕ P=V· Icos (90) P=0 ...

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Power in an AC Circuit

In a AC cir...

Question

In a $A C$ circuit the current is given by $i = 5 sin (100 t - \frac{π}{2})$ and $V = 200 sin (100 t)$ $V$ then power consumption is

20

W

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1000

W

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500

W

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0

W

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AC

V

i

V = 200 sin 100 t Volt

i = 100 sin (100 t + \frac{π}{3}) mA

W .

i = 5 s i n (100 t - \frac{π}{2})

V = 200 s i n (100) v o l t .

A C

V = 200 sin 100 t

I = 5 sin (100 t - \frac{π}{2})

In an AC circuit, V and I are given by, V=100sin(100t)volt, $I = 100 s i n (100 t + \frac{π}{3}) A$ . Then the power dissipated in the circuit is

I = 5 sin (100 t - π / 2)

V = 200 sin (100 t)

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