In a calender, sum of any four number taken in a block can always be written as

4(x + 2)

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4(x + 4)

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2(x + 2)

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2(x + 4)

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Solution

The correct option is B
4(x + 4)

In any calender four number forming a square is always written as

The sum is equal to

= x + x + 1 + x + 7 + x + 8

= 4x + 16

= 4(x + 4)

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