In a certain process $500 c a l$ of heat is given to a system and the system does $100 J$ of work. The increase in internal energy of the system is

40 c a l

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82 c a l

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1993 J

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2193 J

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Solution

The correct option is C $1993 J$
$1 c a l = 4.184 J, t h u s 500 c a l = 2092 J$ .
The change in internal energy is $Δ U = Δ Q - Δ W$
or $Δ U = 2093 - 100 = 1993 J$

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