In a certain process, 525 J of heat is absorbed by a system while 269 J of work is done on the system. What is the change in the internal energy for the process?

256 J

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794 J

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510 J

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300 J

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Solution

The correct option is B 794 J
$Δ Q = + 525 J, Δ W = + 269 J$
From the 1st law of thermodynamics,
$Δ U = (Δ Q + Δ W) = (525 + 269) J = 794 J$

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