Question

In a circle of radius 7 cm, a square ABCD is inscribed. Find the area of the circle which is outside the square.

Answer 1

Square is inscribed in circle so diagonal of square is equal to diameter of circle

Diameter of circle $=2\times 7=14$

Diagonal of square = diameter = 14

So area of square = $\frac{1}{2}\times (diagonal{)}^2=\frac{1}{2}\times 196=98c{m}^2$

Area of circle $=\pi r^2=\frac{22}{7}\times 7^2=154c{m}^2$

Area of the circle which is outside the square = Area of circle - Area of square $=154-98=56c{m}^2$