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Question

In a circle with center O, a perpendicular is dropped from the center to a chord PQ. Find the length of PO, if length of PQ = 24 cm and KO = 5 cm.
  1. 8 cm
  2. 9 cm
  3. 13 cm
  4. 14 cm


Solution

The correct option is C 13 cm
The perpendicular from the centre of a circle to a chord bisects the chord.
PK=KQ=12 cm
Given, KO = 5 cm.
Using Pythagoras theorem in ΔPKO,
we get, (PO)2=(KO)2+(PK)2
(PO)2=52+122
(PO)2=169
PO=13 cm.

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