Question

In a circle with centre O, AB and CD are two arcs such that $\angle AOB={75}^{\circ }$. If arc AB is 3 times of CD, then $\angle COD$ is ${25}^{\circ }$.

• A. True
• B. False

Answer 1

The correct option is A True

$\angle AOB={75}^{\circ }$
Arc AB = 3 $\times$ Arc CD

Angle subtends by arc CD = $\frac{{75}^{\circ }}{3}={25}^{\circ }$.
Hence, the given statement is true.