Question

In a class, $3/5$ of the students are girls and rest are boys. If $2/9$ of the girls and $1/4$ of the boys are absent, what part of the total number of students is present?

• A. $17/25$
• B. $18/49$
• C. $23/30$
• D. $23/36$

Answer 1

Answer: (C)

$23/30$

Girls $=\frac{3}{5}$, Boys $=(1-\frac{3}{5})=\frac{2}{5}$.
Fraction of students absent $=\frac{2}{9}$ of $\frac{3}{5}+\frac{1}{4}$ of $\frac{2}{5}=\frac{6}{45}+\frac{1}{10}=\frac{21}{90}=\frac{7}{30}$.
$\therefore$ Fraction of students present $=(1-\frac{7}{30})=\frac{23}{30}$.