In a class of 180, where boys are twice the number of girls, Kiran (a girl) ranked 34th from the top. If there are 18 boys ahead of Kiran, how many girls are after her in the rank-list?

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None of these

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Solution

The correct option is E
None of these

Number of girls upto the 34th rank = 34 – 18 = 16

Total number of girls = $\frac{180}{(2 + 1)} \times 1$ = 60

Number of girls after the rank of Kiran = 60 – 16 = 44

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In a class of 180, where boys are twice the number of girls, Kiran (a girl) ranked 34th from the top. If there are 18 boys ahead of Kiran, how many girls are after her in the rank-list?

The correct option is E None of these Number of girls upto the 34th rank = 34 – 18 = 16 Total number of girls = 180(2+1)×1 = 60 Number of girls after the rank of Kiran = 60 – 16 = 44

The correct option is E
None of these

Number of girls upto the 34th rank = 34 – 18 = 16

Total number of girls = $\frac{180}{(2 + 1)} \times 1$ = 60

Number of girls after the rank of Kiran = 60 – 16 = 44