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Question

In a closed system :A(s)2B(g)+3C(g) if the partial pressure of C is doubled then partial pressure of B will be:

A
Twice the original preasure
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B
Half of its original preasure
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C
122 times the original pressure
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D
12×2 times its original preasure
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Solution

The correct option is D 12×2 times its original preasure
Solution:- 122 times its original pressure.
For a closed system-
A(s)2B(g)+3C(g)
Kp=(PB)2×(PC)3
Kp(PC)3=(PB)2..........(1)
Since, Kp is constant, thus if the partial pressure of C is doubled then PC=2PC.
Kp=(PB)2×(PC)3
Kp=(PB)2×(2PC)3
Kp(PC)3=8×(PB)2..........(2)
From eqn(1)&(2), we have
8×(PB)2=(PB)2
(PB)2=18×(PB)2
PB=122×PB
Hence, if the partial pressure of C is doubled then partial pressure of B will be 122 times its original pressure.

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