Question

In a common emitter transistor amplifier $\beta$ = 60, $R_0$ = 5000 $\Omega$ and internal resistance of a transistor is 500$\Omega$. The voltage amplification of amplifier will be

• A. 500
• B. 460
• C. 600
• D. 560

Answer 1

The correct option is C 600

$A_v=\beta \frac{R_o}{R_i}=60\times \frac{5000}{500}$ = 600