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Question

In a concave mirror an object is placed at a distance x from the focus, and the image is formed at a distance y from the focus. The focal length of the mirror is


A
xy
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B
xy(xy)
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C
x+y2
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D
xy
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Solution

The correct option is B $$\dfrac{x y}{(x-y)}$$
$$ \begin{array}{l} u=-x \\ v=-y \\ f=+f \\ \dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f} \\ \frac{1}{-y}+\dfrac{1}{x}=\dfrac{1}{+f} \\ \dfrac{x-y}{x y}=\dfrac{1}{f} \\ \dfrac{x y}{(x-y)}=f \end{array} $$

Physics

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