Question

In a conductor, $6.25\times {10}^{16}$ electrons frow from its end A to B in 2 s. Find the current flowing through the conductor. ($e=1.6\times {10}^{-19}C$).

Answer 1

Here, $n=6.25\times {10}^{16}e=1.6\times {10}^{-19}Ct=2s$

So, current, $I=\frac{ne}{t}=\frac{6.25\times {10}^{16}\times 1.6\times {10}^{-19}}{2}=5\times {10}^{-3}A=5mA$\

As electrons are negatively charged, the current flows from B to A.