In a cricket match, a bats-woman hits a boundary $6$ times out of $30$ balls she plays. Find the probability that she did not hit a boundary.

\frac{1}{4}

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\frac{4}{5}

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\frac{1}{3}

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\frac{3}{7}

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Solution

The correct option is C $\frac{4}{5}$
Total number of trials or chances $= 30$ .
Number of chances when the boundary is not hit $= 30 - 6 = 24$
P (The boundary is not hit) $= \frac{24}{30} = \frac{4}{5}$

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In a cricket match, a batsman hits a boundary 6 times out of the 30 balls he plays. Find the probability of him not hitting a boundary on the balls he plays.

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In a cricket match, a bats-woman hits a boundary 6 times out of 30 balls she plays. Find the probability that she did not hit a boundary.

The correct option is C 45Total number of trials or chances =30. Number of chances when the boundary is not hit =30−6=24P (The boundary is not hit) =2430=45

In a cricket match, a bats-woman hits a boundary $6$ times out of $30$ balls she plays. Find the probability that she did not hit a boundary.

The correct option is C $\frac{4}{5}$
Total number of trials or chances $= 30$ .
Number of chances when the boundary is not hit $= 30 - 6 = 24$
P (The boundary is not hit) $= \frac{24}{30} = \frac{4}{5}$