In a cricket match, a batsman hits a boundary 5 times every 30 balls he plays. The probability that he did not hit a boundary is .

\frac{5}{6}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{20}{30}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{1}{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $\frac{5}{6}$
Probability = $\frac{N o . o f f a v o u r a b l e o u t c o m e s}{T o t a l n o . o f o u t c o m e s}$

P (Hitting a boundary) $= \frac{5}{30}$

We know that the sum of all the probabilities is 1.

So, P(not hitting a boundary) $= 1 - \frac{5}{30} = \frac{25}{30} = \frac{5}{6}$

Suggest Corrections

Similar questions

In a cricket match, a batsman hits a boundary 5 times out of the 30 balls he plays .Find the probability he did not hit a boundary.

Q. In a cricket match, a batsman hits a boundary 6 times out of 30 balls he plays.
(i) he hits boundary
(ii) he does not hit a boundary.

In a cricket match, a batsman hits a boundary 6 times out of the 30 balls he plays. Find the probability of him not hitting a boundary on the balls he plays.

In a cricket match, a batsman hit a boundary 6 times (out of 30 balls). Find the probability that next ball he plays is not a boundary.

Q. If a batsman hits boundary 4 times out of 20 balls he plays, then the probability that he did not hit a boundary is ____.

Join BYJU'S Learning Program

In a cricket match, a batsman hits a boundary 5 times every 30 balls he plays. The probability that he did not hit a boundary is .

The correct option is A 56 Probability = No. of favourable outcomesTotal no. of outcomes P (Hitting a boundary) =530 We know that the sum of all the probabilities is 1. So, P(not hitting a boundary) =1−530=2530=56