In a cricket match, a batsman hits a boundary 5 times every 30 balls he plays. Find the probability that he did not hit a boundary.

$\frac{5}{6}$

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$\frac{20}{30}$

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$\frac{4}{5}$

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$\frac{1}{2}$

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Solution

The correct option is A
$\frac{5}{6}$

P (Hitting a boundary) $= \frac{5}{30}$
So, P(not hitting a boundary) $= 1 - \frac{5}{30} = \frac{25}{30} = \frac{5}{6}$

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In a cricket match, a batsman hits a boundary 5 times every 30 balls he plays. Find the probability that he did not hit a boundary.

The correct option is A 56 P (Hitting a boundary) =530 So, P(not hitting a boundary) =1−530=2530=56

The correct option is A
$\frac{5}{6}$

P (Hitting a boundary) $= \frac{5}{30}$
So, P(not hitting a boundary) $= 1 - \frac{5}{30} = \frac{25}{30} = \frac{5}{6}$