In a cricket match, a batsman hits a boundary 5 times out of the 30 balls he plays .Find the probability he did not hit a boundary.

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Solution

The correct option is B. $\frac{5}{6}$
Since batsman plays $30$ balls the total number of trials $n (S) = 30$

Let E be the event of hitting a boundary

$∴ n (E) = 5$

The number of balls not hitting the target $n (E^{'}) = 25$

The probability he does not hit a boundary $= \frac{n (E^{'})}{n (S)} = \frac{25}{30} = \frac{5}{6}$

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The correct option is B. 56Since batsman plays 30 balls the total number of trials n(S)=30 Let E be the event of hitting a boundary ∴n(E)=5 The number of balls not hitting the target n(E′)=25 The probability he does not hit a boundary =n(E′)n(S)=2530=56