Question

In a cricket match, a batsman hits a boundary 6 times out of 30 balls he plays. Find the probability that he did not hit a boundary.

Answer 1

ANSWER:
Number of balls played by the batsman = 30
Number of balls in which he hits boundaries = 6
∴ Number of balls in which he did not hit a boundary = 30 − 6 = 24
P(Batsman did not hit a boundary) = $\frac{\text{Number of balls in which he did not hit a boundary}}{\text{Number of balls played by the batsman}}=\frac{24}{30}=\frac{4}{5}$
Thus, the probability that he did not hit a boundary is $\frac{4}{5}$.