In a cricket match, a batsman hits a sixer $8$ times out of $32$ balls played. Find the probability that a sixer is not hit in a ball

0.75

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0.25

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- 0.25

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0.5

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Solution

The correct option is D $0.75$
Probability of not hitting a sixer in a ball $= 1 -$ probability of hitting a six.
$P = 1 - \frac{8}{32}$
$= 1 - \frac{1}{4}$
$= \frac{3}{4}$
$\Rightarrow P = 0.75$

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In a cricket match, a batsman hits a sixer 8 times out of 32 balls played. Find the probability that a sixer is not hit in a ball

The correct option is D 0.75Probability of not hitting a sixer in a ball =1− probability of hitting a six. P=1−832=1−14 =34 ⇒P=0.75

In a cricket match, a batsman hits a sixer $8$ times out of $32$ balls played. Find the probability that a sixer is not hit in a ball

The correct option is D $0.75$
Probability of not hitting a sixer in a ball $= 1 -$ probability of hitting a six.
$P = 1 - \frac{8}{32}$
$= 1 - \frac{1}{4}$
$= \frac{3}{4}$
$\Rightarrow P = 0.75$