CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In a Δ ABC, BD is the median to the side AC, BD is produced to E such that BD = DE.

Prove that : AE is parallel to BC.

Open in App
Solution


In the given ABC ,

BD is a median

and

BD = DE
In BCDandEAD
CD = DA [BD is median]
BD = DE [given]
BDC=EDA [vertically opposite angle]
By SAS,

BCDtoEAD
Then by cpctc

\(\angle BCD = \angle EAD \)
when angles are equal then

AE is BC .


flag
Suggest Corrections
thumbs-up
11
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Criteria for Congruency
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon