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Question

In a ΔABC, right angled at B, AB=24 cm, BC=7 cm. Determine
(i) sinA,cosA
(ii) sinC,cosC

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Solution

Consider the figure above,

From Pythagoras theorem,

AC2=AB2+BC2

AC2=242+72

AB2=576+49=625

AB=25

Solution(i):
sinθ=oppositeSideHypotenuse

sinA=BCAC=725

cosθ=AdjacentSideHypotenuse

cosA=ABAC=2425


Solution(ii):

sinC=ABAC=2425

cosC=BCAC=725

924849_966349_ans_1ed924b67e7543e295bf33bd4b970111.png

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