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Question

In a ΔABC,tanA2=56 and tanC2=25, then a,b,c are such that


A

b2=ac

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B

2b=a+c

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C

2ac=b (a+c)

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D

a+b=c

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Solution

The correct option is B

2b=a+c


Since,tanA2=56 and tanC2=25tanA2tanC2=56.25Δs(sa).Δs(sc)=13sbs=13sbs=133s3b=s2s=3ba+c=2b


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