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Question

In a ΔABC,tanA+tanB+tanC=6 and tanA.tanB = 6, then tanA, tanB, tanC are ?

A
3,2,1
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B
3,22,73
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C
4,12,32
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D
None of these
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Solution

The correct option is A 3,2,1
tanA + tanB + tanC = 6
tanA.tanB = 6
tanA + tanB + tanC = tanAtanBtanC
tanC=1
tanA and tanB are 2 and 3

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