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Question

In a double slit experiment the angular width of a fringe is found to be 0.2 on a screen placed 1 m away. The wavelength of light used is 600 nm. The angular width of the fringe if entire experimental apparatus is immersed in water is (Takeμwater=43)

A
0.15
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B
1
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C
2
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D
0.3
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Solution

The correct option is C 0.15
Since a fringe of width β is formed on the screen at distance D from the slits, so the angular fringe width
θ=βD=Dλ/dD=λd [β=Dλd]
d=λθ
If the wavelength in water be λ and the angular fringe width be θ, then
d=λθorλθ=λθorθ=λλθ=λ/μλθ[λ=λμ]

θ=0.24/3=0.15

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