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Question

In a factory manufacturing bolts; machines A,B and C manufacture respectively 20%,30% and 50% of the total production. Of their outputs, 2%,3% and 5% are defective bolts. A bolt is drawn at random from the product and is found to be defective. What is the probability that it was manufactured by machine C?

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Solution

Let A,B,C be the events that a bolt selected at random is manufactured respectively by machines A,B and C respectively so that P(A)=210;P(B)=310 and P(C)=510.
Let D be the event that the bolt selected at random is defective, so that
P(D/A)=2100
P(D/B)=3100
And P(D/C)=5100
P(C/D)=P(D/C).P(C)P(D/A)P(A)+P(D/B)P(B)+P(D/C)P(C)
=5×54+9+25=2538

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