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Question 3
In a frequency distribution, the mid-value of a class is 10 and the width of the class is 6. The lower limit of the class is:

A) 6
B) 7
C) 8
D) ​​​​​​​12


Solution

The answer is B.
Let x and y be the upper and lower class limit in a frequency distribution.
Now, mid value of a class =x+y2=10    [given]
x+y=20(i)
Also, given that, width of class = 6
xy=6(ii)
On adding equations (i) and (ii), we get,
2x=20+6
2x=26x=13
On putting x = 13 in (i), we get,
13+y=20y=7
Hence, the lower limit of the class is 7.

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