Question

# In a frequency distribution the mid value of a class is $$15$$ and the class interval is $$4$$. The lower limit of the class is

A
10
B
12
C
13
D
14

Solution

## The correct option is B $$13$$Let the lower limit be l and upper limit be u. Then, $$u - l = 4 ...(1)$$and $$\dfrac{u + l}{2} = 15$$ or $$u + l = 30 ...(2)$$Subtracting $$(2)$$ and $$(1)$$,$$u + l - u + l = 30 - 4$$$$2l = 26$$$$l = 13$$Thus, lower limit $$= 13$$Mathematics

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