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Question

In a frequency distribution the mid value of a class is $$15$$ and the class interval is $$4$$. The lower limit of the class is


A
10
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B
12
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C
13
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D
14
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Solution

The correct option is B $$13$$
Let the lower limit be l and upper limit be u. 
Then, $$u - l = 4 ...(1)$$
and $$\dfrac{u + l}{2} = 15$$ or $$u + l = 30 ...(2)$$
Subtracting $$(2)$$ and $$(1)$$,
$$u + l - u + l = 30 - 4$$
$$2l = 26$$
$$l = 13$$
Thus, lower limit $$= 13$$

Mathematics

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