In a frequency distribution the mid value of a class is 15 and the class interval is 4. The lower limit of the class is
A
10
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B
12
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C
13
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D
14
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Solution
The correct option is B13 Let the lower limit be l and upper limit be u. Then, u−l=4...(1) and u+l2=15 or u+l=30...(2) Subtracting (2) and (1), u+l−u+l=30−4 2l=26 l=13 Thus, lower limit =13