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Physics

Watt Hour Meter

In a house, ...

Question

In a house, $3$ fans of $200$ watt each are used for $12$ hours per day, a TV of $500$ watt is used for $10$ hours per day, $4$ bulbs of $60$ watt each are used for $8$ hours per day. Find the electric bill for the month of $30$ days if the cost of one unit is Rs. $2.20$ .

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Solution

Power of consumption of 3 fans $= 3 \times 200 \times 12 = 7.2 k W h$
Power comsuption of 4 bulbs $= 4 \times 60 \times 8 = 1.92 k W h$
Power comsuption of television = $500 \times 10 = 5 k W h$
Total comsuption of power per day = $7.2 + 1.92 + 5 = 14.12 k W h$
Power consuption in 30 days $= 14.12 \times 30 = 423.6 k W h$
Bill for time period of 30 days $= 423.6 \times 2.20 = R s . 931.92$ .

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In a house, 3 fans of 200 watt each are used for 12 hours per day, a TV of 500 watt is used for 10 hours per day, 4 bulbs of 60 watt each are used for 8 hours per day. Find the electric bill for the month of 30 days if the cost of one unit is Rs. 2.20.

In a house, $3$ fans of $200$ watt each are used for $12$ hours per day, a TV of $500$ watt is used for $10$ hours per day, $4$ bulbs of $60$ watt each are used for $8$ hours per day. Find the electric bill for the month of $30$ days if the cost of one unit is Rs. $2.20$ .