Question

# In a long cylindrical tube the wave level is adjusted and the air column above it is made to vibrate in unison with a vibrating tuning fork kept at the open end. Maximum sound is heard when the air column lengths are equal to

A
λ4 , 3λ4
B
λ2 , 3λ2
C
λ,3λ
D
λ , 3λ4

Solution

## The correct option is A $$\dfrac{\lambda}{4}$$ , $$\dfrac{3\lambda}{4}$$So in general the formula for the resonance length will be:$$\displaystyle \frac{(2n-1)\lambda}{4}$$, where $$n=1, 2, 3$$..First booming sound indicates that at that length, $$l_1$$, of an air column in organ pipes with one end closed is in resonance with the given frequency. And that length is,$$l_1= \lambda /4$$The next resonance length will be :$$l_2=3\lambda/4$$ Physics

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