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Question

In a metre bridge, the gaps are closed by resistances P and Q, P being less than Q. A balance is obtained when the jockey makes contact at a point of bridge wire 40 cm from one end. On shunting the coil Q with a resistance of 50 Ω, the balance point is moved through 10 cm. The resistance P and Q are

A
25 Ω,16.67 Ω
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B
16.67 Ω,25 Ω
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C
10 Ω,25 Ω
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D
8 Ω,12 Ω
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Solution

The correct option is B 16.67 Ω,25 Ω
Balanced condition of meter bridge in 1st case:
PQ=4060=23
Upon shunting Q,
PQ||50Ω=40+106010=1
or P(50+Q)50Q=1
50Q50+Q=23Q
Q=25 Ω
P=23Q=503=16.67 Ω

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