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Byju's Answer
Standard IX
Mathematics
Median of Triangle
In a non-leap...
Question
In a non-leap year the probability of getting
53
Sundays or
53
Thursdays is
A
1
7
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B
2
7
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C
4
7
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D
3
7
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Solution
The correct option is
B
2
7
In anon leap year , there will be
365
days
365
=
7
×
52
+
1
Let us assume that the non leap year starts with sunday , then we have
53
sundays in that year
The next non leap year starts with monday , and has
53
mondays in that year and so on
So the probability of having
53
sundays in non leap year is equal to the probability of having
53
thursdays in non leap year , which is equal to
1
7
Therefore the required probability is
1
7
+
1
7
=
2
7
So the correct option is
B
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0
Similar questions
Q.
In a non-leap year the probability of getting
53
Sundays or
53
Tuesdays or
53
Thursdays is.
Q.
The probability that a leap year will have 53 Fridays or 53 Saturdays is
(a) 2/7
(b) 3/7
(c) 4/7
(d) 1/7
Q.
Find the probability of getting 53 sundays in :
1) a non-leap year
2)leap year
Q.
In a non-leap year, the probability of getting
53
Sundays or
53
Tuesdays or
53
Thursdays is
a
b
,
where
a
and
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are co-prime. Then the value of
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is
Q.
Find the probability of getting
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