CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

In a parallelogram ABCD, AB = 10 cm, AD = 6 cm. The bisector of ∠A meets DC in E, AE and BC produced meet at F. Find te length CF.


Solution



AE is the bisector of A. DAE=BAE =x  BAE=AED=x  (alternate angles)Since opposite angles in ADE are equal, ADE is an isosceles triangle. AD=DE= 6 cm  (sides opposite to equal angles)AB=CD=10 cm CD= DE+ ECEC=CD-DEEC=10-6=4 cmDEA=CEF=x  (vertically opposite angle)EAD=EFC=x  (alternate angles)Since opposite angles in EFC are equal, EFC is an isosceles triangle. CF=CE= 4 cm (sides opposite to equal angles) CF= 4cm

Mathematics
RD Sharma (2019, 2020)
All

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
Same exercise questions
View More


similar_icon
People also searched for
View More



footer-image