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Question

In a photoelectric effect experiment, irradiation of a metal with light of frequency 5.2×1014sec1 yields electrons with maximum kinetic energy 1.3×1019J. Calculate the v0 of the metal.

A
3.2×1014sec1.
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B
1.6×1014sec1.
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C
6.4×1014sec1.
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D
3.2×1015sec1.
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Solution

The correct option is A 3.2×1014sec1.
KE=h(vv0)
Where v= incident frequency,
v0= threshold frequency.
v0=vKEh=5.2×10141.3×10196.626×1034=3.24×1014sec1

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