Question

# In a plane electromagnetic wave, the amplitude of the magnetic field is $$5.0 \times 10^{-6} T$$. Find the amplitude of the electric field and the total average energy density of the wave.

Solution

## $$E = Bc$$$$= 5 \times 10^{-6} \times 3 \times 10^8$$$$= 1.5 \times 10^3 Vm^{-1}$$Energy density =$$\cfrac{1}{2 \mu_0}B^2$$$$= \cfrac{1}{2 \times 4 \pi \times 10^{-7}} \times (5 \times 10^{-6})^2$$$$= 1.0 \times 10^{-5} Jm^{-3}$$ (approx)Physics

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