Question

In a population of 100 rabbits 40 are short-eared. Short ears are recessive to long ears. There are only two alleles for this gene. Long eared are 60 which are in 1:1 ratio of homozygous and heterozygous. Find out the dominant allelic frequency?

• A. 0.55
• B. 0.45
• C. 0.09
• D. 0.37

Answer 1

Answer: (D)

0.37

The frequency of the recessive short-eared"q" allele.

The frequency of qq is 40%, which means that $q^2=0.4$,

If $q^2=0.4$, then q = 0.63, again by definition.

The frequency of the dominant long-eared "p" allele.

Since q = 0.63, and with the help of formula

p + q = 1, p =1-q

hence p = 0.37

So, option D is the correct option.