Question

# In a population of 1000 individuals 360 belongs to genotype AA, 480 to Aa and the remaining 160 to aa. Based on this data, the frequency of allele A in the population is

A
0.4
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B
0.5
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C
0.6
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D
0.7
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Solution

## The correct option is C 0.6According to Hardy - Weinberg principle (p+q)2=p2+3pq+q2=1 where, p = The frequency of allele 'A' q = The frequency of allele 'a' p2 = The Frequency of individual 'AA' q2 = The frequency of individual 'aa' 2pq=The frequency of indi vidual Aa (AA)P2 = 360 out of 1000 individual or P2 =36 out of 100. q2 = 160 our of 1000 or q2 = 16 out of 100. So , q =√0.16=0.4 As p + q = 1 So, p is 0.6

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