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Question

# In a population of 8000, 80 people can not recognize the taste of phenylthiocarbamide. Find out the number of homozygous tasters in given population

A
720
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B
7200
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C
6480
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D
7920
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Solution

## The correct option is C 6480Solution: Answer C: 6480 Genetic taster of PTC is TT or Tt. Non taster are tt.80 people out of 8000 is non tasters and their frequency is 0.01tt. Weinburg equilibrium q2=0.01 So q=0.1, p+q=1,p=1−0.1=0.9 So p2=0.9×0.9=0.81= Frequency of homozygous tasters. Now, since the total population is 8000 and total frequency of homozygous tasters is 0.81Total number of homozygous tasters is x=0.81×8000=6480

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